(2x+3)^2-6x-4=2x(1+2x)

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Solution for (2x+3)^2-6x-4=2x(1+2x) equation: 



(2x+3)^2-6x-4=2x(1+2x)

We move all terms to the left:

(2x+3)^2-6x-4-(2x(1+2x))=0

We add all the numbers together, and all the variables

(2x+3)^2-6x-(2x(2x+1))-4=0

We add all the numbers together, and all the variables

-6x+(2x+3)^2-(2x(2x+1))-4=0



We calculate terms in parentheses: -(2x(2x+1)), so:

2x(2x+1)

We multiply parentheses

4x^2+2x

Back to the equation:

-(4x^2+2x)



We get rid of parentheses

-4x^2-6x+(2x+3)^2-2x-4=0

We add all the numbers together, and all the variables

-4x^2-8x+(2x+3)^2-4=0

We move all terms containing x to the left, all other terms to the right

-4x^2-8x+(2x+3)^2=4

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